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Suppose unknowingly you wrote the universal gravitational constant value as G=6.67xx10^(11) instead of the correct value G=6.67xx10^(-11), what is the acceleration due to gravity g' for this incorrect G? According to this new acceleration due to gravity, what will be your weight W? |
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Answer» Solution :INCORRECT value of G`=6.67xx10^(11)` `g=(GM)/(R^2)` `M_(E)=6.02xx10^(24)KG` `R_(E)=6.4xx10^(6)` `g'=(6.67xx10^(11)xx6.02xx10^(24))/((6.4xx10^6)^(2))` `=(40.1534)/(40.96)xx10^(11+24-12)` `=0.9798xx10^(35-12)` `=0.9798xx10^(23)` `=9.798xx10^(22)` `g'=9.798xx10^(22)` `=9.8xx10^(22)` If mass m = 1 then WEIGHT `W'=mg'=9.8xx10^(22)` `W'=9.8xx10^(22)W` |
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