1.

Suppose unknowingly you wrote the universal gravitational constant value as G=6.67xx10^(11) instead of the correct value G=6.67xx10^(-11), what is the acceleration due to gravity g' for this incorrect G? According to this new acceleration due to gravity, what will be your weight W?

Answer»

Solution :INCORRECT value of G`=6.67xx10^(11)`
`g=(GM)/(R^2)`
`M_(E)=6.02xx10^(24)KG`
`R_(E)=6.4xx10^(6)`
`g'=(6.67xx10^(11)xx6.02xx10^(24))/((6.4xx10^6)^(2))`
`=(40.1534)/(40.96)xx10^(11+24-12)`
`=0.9798xx10^(35-12)`
`=0.9798xx10^(23)`
`=9.798xx10^(22)`
`g'=9.798xx10^(22)`
`=9.8xx10^(22)`
If mass m = 1
then WEIGHT `W'=mg'=9.8xx10^(22)`
`W'=9.8xx10^(22)W`


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