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Suppose we have a simple computer with control unit holding a PC with a 32 bit address + Arithmetic unit holding one double length 64 bit Arithmetic Register. The number of states the finite machine will hold:(a) 2^(32*64)(b) 2^96(c) 96(d) 32This question was posed to me in examination.Question is from Programming Techniques-Storage and Subroutines topic in chapter Introduction to Turing Machines of Automata Theory

Answer»

The correct answer is (b) 2^96

Easy EXPLANATION: ACCORDING to the statistics of the question, we will have a FINITE machine with 2^96 STATES.



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