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Suppose we have four boxes A,B,C and D containing coloured marbles as given below :One of the boxes has been selected at random and a single marble is drawn from it. If the marble is red, what is the probability that it was drawn from box A? box B?, box C? |
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Answer» Probablity of selecting red ball from Box A,`P(R/A) = 1/10` Probablity of selecting red ball from Box B,`P(R/B) = 6/10 =3/5` Probablity of selecting red ball from Box C,`P(R/C) = 8/10 =4/5` Probablity of selecting red ball from Box D,`P(R/D) = 0/10 =0` Probablity of selected red ball is from Box A, `P(A/R)` can be given by, `P(A/R) = (P(R/A))/(P(R/A)+P(R/B)+P(R/C)+P(R/D))` `=(1/10)/(1/10+3/5+4/5) = 1/15` Probablity of selected red ball is from Box A, `P(A/R)` can be given by, `P(A/R) = (P(R/A))/(P(R/A)+P(R/B)+P(R/C)+P(R/D))` `=(1/10)/(1/10+3/5+4/5) = 1/15` Probablity of selected red ball is from Box B, `P(B/R)` can be given by, `P(B/R) = (P(R/B))/(P(R/A)+P(R/B)+P(R/C)+P(R/D))` `=(3/5)/(1/10+3/5+4/5) = 6/15=2/5` Probablity of selected red ball is from Box B, `P(B/R)` can be given by, `P(C/R) = (P(R/C))/(P(R/A)+P(R/B)+P(R/C)+P(R/D))` `=(4/5)/(1/10+3/5+4/5) = 8/15` |
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