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Suppose z is any root of 11z8+20iz7+10iz–22=0, where i=√−1 . Then S=|z|2+|z|+1 satisfies |
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Answer» Suppose z is any root of 11z8+20iz7+10iz–22=0, where i=√−1 . Then S=|z|2+|z|+1 satisfies |
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