Surface mass density of disc of mass `m` and radius `R` is `alpha-Kr^(2)`. Then its moment of inertia `w.r.t.` axis of rotation passing through center and perpendicular to the plane of disc is :A. `1=(3)/(2)nR^(2)`B. `1=(4)/(3)nR^(2)`C. `1-(2)/(5)nR^(2)`D. `1-(2)/(3)nR^(2)`

Surface mass density of disc of mass `m` and radius `R` is `alpha-Kr^(

1.	Surface mass density of disc of mass `m` and radius `R` is `alpha-Kr^(2)`. Then its moment of inertia `w.r.t.` axis of rotation passing through center and perpendicular to the plane of disc is :A. `1=(3)/(2)nR^(2)`B. `1=(4)/(3)nR^(2)`C. `1-(2)/(5)nR^(2)`D. `1-(2)/(3)nR^(2)`
Answer» Correct Answer - D

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Surface mass density of disc of mass `m` and radius `R` is `alpha-Kr^(2)`. Then its moment of inertia `w.r.t.` axis of rotation passing through center and perpendicular to the plane of disc is :A. `1=(3)/(2)nR^(2)`B. `1=(4)/(3)nR^(2)`C. `1-(2)/(5)nR^(2)`D. `1-(2)/(3)nR^(2)`

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