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Surface tension of mercury is 540 `dy"ne"//cm`. What will be its value when unit of mass of 1kg. Unit of length is 1m and unit of time is 1 minute?

Answer» Here, `n_1 =540 "dyne"//cm`.
`M_1 =1g,L_1 = 1cm, T_1 =1` sec
`n_2 =? M_2 =1 kg, L_2 =1m, T_2 = 1 min =60s`
Surface tension ` = ("force")/("length") =(MLT^(-2))/(L) =[M^1 L^ 0 T^(-2)]`
`n_2 = n_1((M_1)/(M_2))^1 ((L_1)/(L_2))^0 ((T_1)/(T_2))^(-2) = 540 ((1g)/(1kg))^1 xx1((1s)/(60s))^(-2)`
`n_2 = 540xx10^(-3)xx60xx60 = 1944` new units of surface tension


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