1.

Surface tension of water is 73 dyne cm^(-1) at 20^(@)C. If surface area is increased by 0.10" m"^(2), work done will be

Answer»

73 ergs
730 ergs
7300 ergs
73000 ergs

Solution :Work done=Surface tension xxIncrease in surface AREA
`=73" dyne "CM^(-1)xx0.1" m"^(2)`
`=73" dynwe "cm^(-1)xx0.1xx10^(4)"ergs"`
`=7.3xx10^(4)" dyne " cm=7.3xx10^(4)" ergs"`


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