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InterviewSolution
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| Answer» TION:equation is,v^2-u^2=2asv 2 −u 2 =2asWe need to prove this equationUsing diagramDisplacement covered during the time interval ist'-t=Area\ of\ ABtt't ′ −t=Area of ABtt ′ Area\ of\ TRAPEZIUM=Area\ of\ triangle\ ABA'+Area\ of\ rectangle\ AA't'tArea of trapezium=Area of triangle ABA ′ +Area of rectangle AA ′ t ′ tArea\ of\ trapezium=\dfrac{1}{2}\times\ SUM\ of\ parallel\ sides\times\ perpendicular\ distanceArea of trapezium= 21 × sum of parallel sides× perpendicular distancePut the value into the formulas=\dfrac{1}{2}(v+u)\times ts= 21 (v+u)×tPut the value of t from equation of motions=\dfrac{1}{2}(v-u)\times\dfrac{v-u}{a}s= 21 (v−u)× av−u 2as=v^2-u^22as=v 2 −u 2 v^2-u^2=2asv 2 −u 2 =2asHence, This is proved | |