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System shown in figure is released from rest . Pulley and spring is mass less and friction is absent everywhere. The speed of `5 kg` block when `2 kg` block leaves the constant of with ground is (force constant of spring `k = 40 N//m and g = 10 m//s^(2))` A. `sqrt(2) m//s`B. `2sqrt(2) m//s`C. `2 m//s`D. None of these |
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Answer» Correct Answer - 2 Let x be the extension is spring when 2 kg block leaves the constant with ground. Then kx = 2g. `x = (2g)/(k)= (2xx 10)/(40) = (1)/(2)m` Now from conservation of energy , `mgx = (1)/(2) Kx^(2) +(1)/(2)mv^(2)` `rArr v=sqrt(2gx-(kx^(2))/(m))` `=2sqrt(2)m//s` |
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