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Table `IfDelta_(r)=|{:(,(2r), x, N(N+1)),(,(6r^(2)-1),y, N^(2)(2N+3)),(,(4r^(3) - 2Nr), z, N^(3)(N+1)):}|` where N `in` natural numbers. Then `sum_(r=1)^(N) Delta_(r)` isA. NB. `N^(2)`C. ZeroD. None of these |
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Answer» Correct Answer - 3 `underset(r=1)overset(N)sumDelta_(r)=|{:(,2N((N+1))/(2), x, N(N+1)),(,6N((N+1)(2N+1))/(6),y, N^(2)(2N+3)),(,4[(N(N+1))/(2)] -2N.(N(N+1))/(2), z, N^(3)(N+1)):}|=0` |
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