1.

Take 25 ml water in a beaker and the pass electricity through it. Then add little sulphuric acid in it. a. Why electricity didn’t pass through pure water? b. What happens when dil H2SO4  is added?c. Which type of ion formed more when sulphuric acid is added in water? d. Complete the equation of the Ionization of H2SO4 H2SO4 → 2H+ Based on the equation given below write down the correct answers. 2H+  + 2H2O → 2H3O +  + SO2-4e. Complete the equation. f. Write down the name of H3O+ ion? g. Which ion is moving towards negative ion? h. Complete the reaction taking place in the negative electrode. 2H3O+ (aq) + 2e- →  + i. Which ion is having highest oxidation potential? j. Complete the reaction taking place in positive electrode. 2H2O → 4H+ k. Ions remain in the beaker after the electrolysis are I. What product form when these two combined together

Answer»

a. Since the number of ions is less, pure water does not allow the passage of electricity. 

b. When dil H2SO4 is added the water becomes a good electrolyte. Hence electricity passes through it. When a little dilute sulphuric acid is mixed with water large quantity of hydronium ions are formed.

c. Hydronium ion (H3O+

d. H2SO4 → 2H+ + SO2-4 

e. 2H+ + SO2-4  + 2H2O → 2H3O+ + SO2-4 

f. Hydronium ion 

g. H3O+ 

h. 2H3O+ (aq) + 2e- → H2(g) + 2H2

i. H2O has the highest oxidation potential when compared to SO2-4 

j. 2H2O → O2(g) + 4H+ + 4e- 

k. 4H+ , SO42- ions. 

l. H2SO4 is formed when these 2 combine together.



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