1.

`tan^(-1)""(1)/(2)+tan^(-1)""(1)/(3)`

Answer» `tan^(-1)""(1)/(2)+tan^(-1)""(1)/(3)=tan^(-1)""((1)/(2)+(1)/(3))/(1-(1)/(2)xx(1)/(3))`
`=tan^(-1)1=tan^(-1)tan""(pi)/(4)=(pi)/(4)`


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