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`tan^(-1)""(1-x)/(1+x)=(1)/(2)tan^(-1)x,(xgt0)` |
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Answer» `tan^(-1)""(1-x)/(1+x)=(1)/(2)tan^(-1)x,(xgt0)` `impliestan^(-1)-tan^(-1)x=(1)/(2)tan^(-1)x` `implies(pi)/(4)=(1)/(2)tan^(-1)x+tan^(-1)x` `implies(3)/(2)tan^(-1)x=(pi)/(4)` `impliestan^(-1)x=(pi)/(6)` `impliesx=tan""(pi)/(6)=(1)/(sqrt3)` |
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