1.

`tan^(-1)""(1-x)/(1+x)=(1)/(2)tan^(-1)x,(xgt0)`

Answer» `tan^(-1)""(1-x)/(1+x)=(1)/(2)tan^(-1)x,(xgt0)`
`impliestan^(-1)-tan^(-1)x=(1)/(2)tan^(-1)x`
`implies(pi)/(4)=(1)/(2)tan^(-1)x+tan^(-1)x`
`implies(3)/(2)tan^(-1)x=(pi)/(4)`
`impliestan^(-1)x=(pi)/(6)`
`impliesx=tan""(pi)/(6)=(1)/(sqrt3)`


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