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`tan^(-1)[2cos(2sin^(-1)""(1)/(2))]` |
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Answer» `tan^(-1)[2cos(2sin^(-1)""(1)/(2))]` `=tan^(-1)[2cos(2sin^(-1)sin""(pi)/(6))]` `=tan^(-1)[2cos(2.(pi)/(6))]` `=tan^(-1)[2.cos""(pi)/(3)]` `=tan^(-1)(2.(1)/(2))=tan^(-1)(1)` `tan^(-1)(tan""(pi)/(4))=(pi)/(4)` |
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