InterviewSolution
Saved Bookmarks
| 1. |
`tan^(2)(2x-3)` |
|
Answer» `int tan^(2)(2x-3)dx" माना "2x-3=t` `=int tan^(2)t(dt)/(2)" "rArr 2dx=dt` `=(1)/(2)int(sec^(2)t-1)dt" "rArr dx=(dt)/(2)` `=(1)/(2)(tant-t)dt` `=(1)/(2)[sec(2x-3)-2x+3]+c_(1)` `=(1)/(2)sec^(2)(2x-3)-x+c" जहाँ "c=c_(1)+(3)/(2)` |
|