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`tan^(2)(2x-3)`

Answer» `int tan^(2)(2x-3)dx" माना "2x-3=t`
`=int tan^(2)t(dt)/(2)" "rArr 2dx=dt`
`=(1)/(2)int(sec^(2)t-1)dt" "rArr dx=(dt)/(2)`
`=(1)/(2)(tant-t)dt`
`=(1)/(2)[sec(2x-3)-2x+3]+c_(1)`
`=(1)/(2)sec^(2)(2x-3)-x+c" जहाँ "c=c_(1)+(3)/(2)`


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