1.

\tan ^{2} \frac{\pi}{6}+\tan ^{2} \frac{\pi}{4}+\tan ^{2} \frac{\pi}{3}=\frac{13}{3}

Answer»

tanπ/6=1/√3 tanπ/4=1 tanπ/3=√3squaring and adding1/3+1+3=1/3+4=13/3



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