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`tan^(3)2xsec 2x` |
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Answer» माना `I=int tan^(3)2x.sec2xdx` `=int(tan^(2)2x).(tan2x).sec2x dx` `= int(sec^(2)2x-1).(tan2x.sec2x)dx` माना `sec2x=t` `rArr" "2sec 2x. Tan 2x=(dt)/(dx)` `rArr" "sec 2x. Tan 2x dx=(dt)/(2)` `I=int(t^(2)-1)(dt)/(2)` `=(1)/(2)[(t^(3))/(3)-t]+c` `=(1)/(6)sec^(3)2x-(1)/(2)sec2x+c` |
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