` tan alpha + 2 tan 2alpha + 4 tan4alpha + 8 cot8alpha` is equal to :

1.	` tan alpha + 2 tan 2alpha + 4 tan4alpha + 8 cot8alpha` is equal to :
Answer» `8cot8alpha` `8(cot^24alpha-1)/(2cot4alpha)` `4cot4alpha-4tan4alpha` `4(cot^2 2alpha-1)/(2cot2alpha)-4tan4alpha` `2cot2alpha-2tan2alpha-4tan4alpha` `cotalpha-tanalpha-2tan2alpha-4tan4alpha` `=cotalpha` option c is correct.

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` tan alpha + 2 tan 2alpha + 4 tan4alpha + 8 cot8alpha` is equal to :

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