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`tan(sin^(-1)""(3)/(5)+cot^(-1)""(3)/(2))` |
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Answer» `tan(sin^(-1)""(3)/(5)+cot^(-1)""(3)/(2))` `=tan[tan^(-1)""((3)/(5))/(sqrt(1-((3)/(5))^(2)))+tan^(-1)""(2)/(3)]` `=tan[tan^(-1)""(3)/(4)+tan^(-1)""(2)/(3)]` `tan[tan^(-1)""((3)/(4)+(2)/(3))/(1-(3)/(4).(2)/(3))]=((9+8)/(12))/((12-6)/12)=(17)/(6)` |
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