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tanA +secA -1÷tanA-secA+1 |
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Answer» tanA + secA -1 / tanA -secA + 1= (sinA +1-cosA) /(sinA+cosA-1 ) × (sinA+cosA +1)/(sinA+cosA+1) = (sinA+cosA )(sinA-cosA)+sinA+cosA-cosA+1+sinA-cosA/(sinA+cosA)2-12) after simplification this is equal to = 2sinA(1+sin A)/ 2sinA cosA = (1+sin A)/ cosA =1/cosA+sinA/cosA=secA+tanA |
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