1.

tanA +secA -1÷tanA-secA+1

Answer»

tanA + secA -1 / tanA -secA + 1= (sinA +1-cosA) /(sinA+cosA-1 ) × (sinA+cosA +1)/(sinA+cosA+1)

= (sinA+cosA )(sinA-cosA)+sinA+cosA-cosA+1+sinA-cosA/(sinA+cosA)2-12)

after simplification this is equal to

= 2sinA(1+sin A)/ 2sinA cosA

= (1+sin A)/ cosA

=1/cosA+sinA/cosA=secA+tanA



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