तब-sec B+ tan 872. यदि sec B =४+का मान है :4

1.	तब-sec B+ tan 872. यदि sec B =४+का मान है :4x
Answer» Let beta = A Given:secA = x + 1/4x As, 1 + tan^2A = sec^2Atan^2A = sec^2A – 1 Therefore, tan^2A = (x + 1/4x)^2 -1= x^2 + 2x1/4x + 1/16x^2 – 1= x^2 + 1/2 + 1/16x2 – 1= x^2 + 1/16x^2 – 1/2= (x – 1/4x)^2 So, tan A = (x – 1/4x) or tan A = - (x – 1/4x) Substitute the value of secA and tanA in the given equation secA + tanA For (tan A = (x - 1/4x)) secA + tanA= x + 1/4x + x – 1/4x= 2x For (tan A = - (x - 1/4x)) secA + tanA= x + 1/4x - x + 1/4x= 2/4x= 1/2x

तब-sec B+ tan 872. यदि sec B =४+का मान है :4x

Answer»

Let beta = A

Given:secA = x + 1/4x

As, 1 + tan^2A = sec^2Atan^2A = sec^2A – 1

Therefore, tan^2A = (x + 1/4x)^2 -1= x^2 + 2*x*1/4x + 1/16x^2 – 1= x^2 + 1/2 + 1/16x2 – 1= x^2 + 1/16x^2 – 1/2= (x – 1/4x)^2

So, tan A = (x – 1/4x) or tan A = - (x – 1/4x)

Substitute the value of secA and tanA in the given equation secA + tanA

For (tan A = (x - 1/4x)) secA + tanA= x + 1/4x + x – 1/4x= 2x For (tan A = - (x - 1/4x)) secA + tanA= x + 1/4x - x + 1/4x= 2/4x= 1/2x