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Temperature of onemole of helium gas is increased by 1^(@)C. Hence,the increasein its internal energy will be |
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Answer» 2 CAL But for MONOATOMIC GAS, `C_(v)= (3)/(2) R`. Also `DeltaT =1^(@)` (Given) Hence, `DeltaU = C_(v)DeltaT = (3)/(2) R = (3)/(2) xx2 = 3 cal` |
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