1.

Temperature of onemole of helium gas is increased by 1^(@)C. Hence,the increasein its internal energy will be

Answer»

2 CAL
3 cal
4 cal
5 cal

Solution :`C_(v) = ((DeltaU)/(DeltaT))_(V)`or` DeltaU = C_(v)DeltaT`
But for MONOATOMIC GAS,
`C_(v)= (3)/(2) R`. Also `DeltaT =1^(@)` (Given)
Hence, `DeltaU = C_(v)DeltaT = (3)/(2) R = (3)/(2) xx2 = 3 cal`


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