Temperature of substances A and B are 727^(@)C and 327^(@)C respectively, then ratio of rate of their radiant energy H_(A):H_(B)=. . . . .

Temperature of substances A and B are 727^(@)C and 327^(@)C respective

1.	Temperature of substances A and B are 727^(@)C and 327^(@)C respectively, then ratio of rate of their radiant energy H_(A):H_(B)=. . . . .
Answer» `727:327` `5:3` `25:9` `625:81` Solution :`T_(A)=273+727=1000K` `T_(B)=273+327=600K` Rate of RADIANT energy `HpropT^(4)` `:.(H_(A))/(H_(B))=(T_(A)^(4))/(T_(B)^(4))` `=((1000)^(4))/((600)^(4))` `=((10)/(6))^(4)` `=((5)/(3))^(2)` `=(625)/(81)` `:.H_(A):H_(B)=625:81`