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Ten cells each of emf `1 V` and internal resistance `1Omega` are connected inseries. In this arrangement, polarity of two cells is reversed and the system is connected to an external resistance of `2Omega`. Find the current in the circuit. |
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Answer» Correct Answer - A::B Net emf `=(n-2m)E` `=(10-2xx2)(1)` `=6V` `i=("Net emf")/("Net resistance")` `=6/(10+2)=0.5A` |
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