Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is 10g and acceleration due to gravity is 10 ms^(-2), what is the magnitude and direction of the force on the 7^(th) coin (counting from the bottom) due to all the coins above it ?

Ten coins are placed on top of each other on a horizontal table. If th

1.	Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is 10g and acceleration due to gravity is 10 ms^(-2), what is the magnitude and direction of the force on the 7^(th) coin (counting from the bottom) due to all the coins above it ?
Answer» 0.3 N downwards 0.3 N upwards 0.7 N downwards 0.7 N upwards Solution :FORCE on the seventh COIN = weight of the THREE coins above it. `F=3mg`