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Ten men, working for 6 days of 10 hours each,521finish of a piece of work. How many menworking at the same rate and for the samenumber of hours each day, will be required tocomplete the remaining work in 8 days? |
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Answer» Ans :- Here time and capacity is same so we will not consider them. 10 men complete 5/21 work in 6 daysMeans 1 man will complete 5/21 work in 60 days 1 man complete whole work in 60*21/5 = 252 days 1 man will complete 16/21 work in 252*16/21 = 192 days To finish work in 192 days, man required = 1to finish work in 1 days , men required = 192to finish work in 8 days, men required = 192/*8 = 24 men |
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