1.

Ten moles of an ideal gas at constant temperature 600 K is compressed from 100l to 10L. The work done in the process is ……………. .

Answer»

`4.11xx10^(4)J`
`-4.11xx10^(4)J`
`11.4xx10^(4)J`
`-11.4xx10^(4)J`

SOLUTION :The process is isothermal. The work DONE is
`W=nRT ln ((V_(2))/(V_(1)))=2.3026xx10xx8.3xx600xxlog_(10)((10)/(100))rArr W=-11.4xx10^(4)J`


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