InterviewSolution
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InterviewSolution
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Ten moles of `(O_2)` gas are kept at temperature `T`. At some higher temperature `2T`, fourty percent of molecular oxygen breaks into atomic oxygen. Find change in internal energy of the gas. |
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Answer» Correct Answer - A::B::D Initial energy Using the relation, `U = (nf)/2 RT` we have, `n = 10, f = 5` for diatomic `O_(2)` gas `U_i = (10 xx 5)/2(RT) = 25 RT` Final energy fourty percent means 4 moles `O_(2)` breaks into `O`. So, it will become `8 moles` of monoatomic gas (O). remaining 6 moles are of diatomic gas `(O_(2)`. But now the new tempreature is (2 T). `:. Uf =(8 xx 3)/2(R) (2T) +(6 +5)/2(R)(2T) =54 RT` So, change in internal energy, `DeltaU = Uf -U_i = 29RT`. |
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