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Ten one-rupee coins are put on top of each other on a table.Each coin has a mass m. Give the magnitude and direction of (a) the force on the7th coin (counted from the bottom) due to all the coins on its top, (b) the force on the 7th coin by the eighth coin, (c) the reaction of the 6th coin on the 7th coin |
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Answer» Solution : Letmass ofeachcoin = m Noofcoin =10 ![]() (a ) Forceactingon `7^(TH)`coindue toremainingcoinaboveit . Therewill be3coinabove`7^(th)`COIN= weightof 3 coins Letmass ofeachcoin = m Noofcoin =10 ( B)forceactingon `7^(th) ` coindue to`8^(th)`coin =weightof `8^(th)` + weight2coinaboveit . =mg +2 mg Letmass ofeachcoin = m Noofcoin =10 (c )THEREACTIONOF the `6^(th)`coin on the `7^(th)` coin =-(forceactingon the `6^(th)` coin) ` =- (4 mg N` |
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