InterviewSolution
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InterviewSolution
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Ten positively charged particles are kept fixed on the x-axis at points x=10cm, 20cm, 30cm, …, 100cm. The first particle has a charge `1.0xx 10^(-8)C`, the second `8xx10^(-8)` C, the third `27xx10(-8)`C and so on. The tenth particle has a charge `1000xx10^(-8)C.` find the magnitude of the electric force acting on a 1 C charge placed at the origin. |
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Answer» By superposition principle, force on charge 1C placed at origin `F_(0) = F_(01) + F_(02) +…. + F_(010)` = `(q_(0))/(4pi in_(0)) [(q_(1))/(r_(1)^(2)) + (q_(2))/(r_(2)^(2)) + (q_(10))/(r_(n)^(2))]` = `9xx10^(9)xx1 [(1.0xx10^(-8))/((0.10)^(2)) + (8xx10^(-8))/((0.20)^(2)) + (27xx10^(-8))/((0.30)^(2)) +(1000xx10^(-8))/((1.00)^(2))]` `= 9xx10^(9)xx10^(-6) [1+2+3+...+10]` = `9xx10^(3)xx55 = 4.95xx10^(5)N` |
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