Terminal alkyne is very weak acid, it forms salt with very strong base such as NaNH_(2) and sodium metal. R-C-=C-Hunderset(NH_(3)(l))overset(NaNH_(2))toR-C-=overset(ө)(C)overset(o+)(N)a+(1)/(2)H_(2) Sodium salt of alkyne is known as shown alkynide. sodium alkynide is hydrolysed with water because it is salt. Sodium salt behaves as nucleophile as well as strong base. for P-alkyl halides it behaves as a cucleophile. thus primary alkylhalides gives SN reaction halids it behaves as strong base hence they undergo elimination reaction. Q. R-CH_(2)-C=ClIunderset(NH_(3)(l))overset(Na)toPoverset(CH_(3)-CH_(2)Br)toR. R is

Terminal alkyne is very weak acid, it forms salt with very strong base

1.	Terminal alkyne is very weak acid, it forms salt with very strong base such as NaNH_(2) and sodium metal. R-C-=C-Hunderset(NH_(3)(l))overset(NaNH_(2))toR-C-=overset(ө)(C)overset(o+)(N)a+(1)/(2)H_(2) Sodium salt of alkyne is known as shown alkynide. sodium alkynide is hydrolysed with water because it is salt. Sodium salt behaves as nucleophile as well as strong base. for P-alkyl halides it behaves as a cucleophile. thus primary alkylhalides gives SN reaction halids it behaves as strong base hence they undergo elimination reaction. Q. R-CH_(2)-C=ClIunderset(NH_(3)(l))overset(Na)toPoverset(CH_(3)-CH_(2)Br)toR. R is
Answer» `R-C-=C-CH_(2)-CH_(2)-CH_(3)` `R-CH_(2)-CH_(2)-C-=C-CH_(3)` `R-CH_(2)-C-=C-CH_(2)-CH_(3)` `R-CH_(2)-CH_(2)-CH_(2)-C-=CH` ANSWER :C