Terminal alkyne is very weak acid, it forms salt with very strong base such as NaNH_(2) and sodium metal. R-C-=C-Hunderset(NH_(3)(l))overset(NaNH_(2))toR-C-=overset(ө)(C)overset(o+)(N)a+(1)/(2)H_(2) Sodium salt of alkyne is known as shown alkynide. sodium alkynide is hydrolysed with water because it is salt. Sodium salt behaves as nucleophile as well as strong base. for P-alkyl halides it behaves as a cucleophile. thus primary alkylhalides gives SN reaction halids it behaves as strong base hence they undergo elimination reaction. Q. CH_(3)-overset(Br)overset(|)(C)H-CH_(3)overset(R-C-=overline(C)overset(+)(N)a)toS+T+Br^(-) S and T are

Terminal alkyne is very weak acid, it forms salt with very strong base

1.	Terminal alkyne is very weak acid, it forms salt with very strong base such as NaNH_(2) and sodium metal. R-C-=C-Hunderset(NH_(3)(l))overset(NaNH_(2))toR-C-=overset(ө)(C)overset(o+)(N)a+(1)/(2)H_(2) Sodium salt of alkyne is known as shown alkynide. sodium alkynide is hydrolysed with water because it is salt. Sodium salt behaves as nucleophile as well as strong base. for P-alkyl halides it behaves as a cucleophile. thus primary alkylhalides gives SN reaction halids it behaves as strong base hence they undergo elimination reaction. Q. CH_(3)-overset(Br)overset(\|)(C)H-CH_(3)overset(R-C-=overline(C)overset(+)(N)a)toS+T+Br^(-) S and T are
Answer» `CH_(3)-CH_(2)-CH_(3),R-C-=CH` `CH_(3)-CH=CH_(2),R-C-=CH` `CH_(3)-CH=CH_(2),R-CH_(2)-CH_(3)` `CH_(3)-C-=CH,R-C-=CH` ANSWER :B