1.

Terminal alkyne is very weak acid, it forms salt with very strong base such as NaNH_(2) and sodium metal. R-C-=C-Hunderset(NH_(3)(l))overset(NaNH_(2))toR-C-=overset(ө)(C)overset(o+)(N)a+(1)/(2)H_(2) Sodium salt of alkyne is known as shown alkynide. sodium alkynide is hydrolysed with water because it is salt. Sodium salt behaves as nucleophile as well as strong base. for P-alkyl halides it behaves as a cucleophile. thus primary alkylhalides gives SN reaction halids it behaves as strong base hence they undergo elimination reaction. Q. CH_(3)-overset(Br)overset(|)(C)H-underset(Br)underset(|)(C)H_(2)underset((ii)NaNH_(3)Delta)overset((i)C_(2)H_(3)ONa,Delta)toVunderset((ii)H_(2)O)overset((i).CO_(2))toW is

Answer»

`CH_(3)-CH_(2)CH_(2)COOH`
`CH_(3)C-=C-COOH`
`CH_(3)-CH=CH-COOH`
`CH_(3)-underset(CH_(3))underset(|)(C)H-COOH`

ANSWER :B


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