the 1st,2nd and 3rd ionization energies of an element are 7ev, 12.5 ev

1.	the 1st,2nd and 3rd ionization energies of an element are 7ev, 12.5 ev and 42.5 ev respectively. the most stable oxidation state of the element will be???
Answer» To remove the first electron, you need to provide 7eV, to remove the second one; you need to ACCESS between 12.5eV and 42.5eV that is required to remove the third electron. This GIVES you the most stable oxidation state for this element to be +2. Here the 3rd and 2nd ionization enthalpy difference is more than 15 EV and EVALUATE it ACCORDINGLY.

the 1st,2nd and 3rd ionization energies of an element are 7ev, 12.5 ev and 42.5 ev respectively. the most stable oxidation state of the element will be???

Answer»

To remove the first electron, you need to provide 7eV, to remove the second one; you need to ACCESS between 12.5eV and 42.5eV that is required to remove the third electron.

This GIVES you the most stable oxidation state for this element to be +2.

Here the 3rd and 2nd ionization enthalpy difference is more than 15 EV and EVALUATE it ACCORDINGLY.

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the 1st,2nd and 3rd ionization energies of an element are 7ev, 12.5 ev and 42.5 ev respectively. the most stable oxidation state of the element will be???

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