1.

The 21st term of the AP whose first two terms are –3 and 4 is(A) 17 (B) 137 (C) 143 (D) –143

Answer»

The correct answer is (b) 137.

Explanation:

In the given AP, t1 = -3 and t2 = 4

d = t2 - t1 

= 4 - (-3) 

= 7

tn = a + (n-1)d

t21 = (-3) + (21-1)(7) 

= 137



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