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The 21st term of the AP whose first two terms are –3 and 4 is(A) 17 (B) 137 (C) 143 (D) –143 |
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Answer» The correct answer is (b) 137. Explanation: In the given AP, t1 = -3 and t2 = 4 d = t2 - t1 = 4 - (-3) = 7 tn = a + (n-1)d t21 = (-3) + (21-1)(7) = 137 |
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