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The `500 muF` capacitor is charged at a steady rate of `100 mu C//s`. The potential difference across the capacitor will be 10 V after an interval ofA. 5 sB. 10 sC. 50 sD. 100 s |
Answer» Correct Answer - C Charge, `Q=CV=500muFxx10V=5xx10^(-3)C` Now, `Q=qt" to "t=(Q)/(q)` or Time taken to raise the potential difference `t=(5xx10^(-3))/(100xx10^(-6))=(1)/(20)xx1000s=50s` |
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