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The 5th term of an AP is -3 and its common difference is -4. The sum of its first 10 terms isA. 50B. `-50`C. 30D. `-30` |
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Answer» Correct Answer - B `a+4d = -3 "and" d = -4`. So, a = 13 `therefore S_(10) = (10)/(2) [2a +9d] = 5 [2 xx 13 + 9xx (-4)] = -50` |
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