The abgular acceleration the toppling pole shown in figure is given alpha="k "sin theta, where theta is te angle between the axis of the pole and the vertical and k is a constant. The pole starts from rest at theta=0. Choose the correct options

The abgular acceleration the toppling pole shown in figure is given al

1.	The abgular acceleration the toppling pole shown in figure is given alpha="k "sin theta, where theta is te angle between the axis of the pole and the vertical and k is a constant. The pole starts from rest at theta=0. Choose the correct options
Answer» The tangntial acceleration of the end of the POLE is `LK SINTHETA` The CENTRIPETAL acceleration of the end of the pole is `2kl(1-costheta)` The tangntial acceleration of the end of the pole is `2kl(1-costheta)` The centripetal acceleration of the end of the pole is `lksintheta` ANSWER :A::B