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The abscissa of the points of the curve y = x3 in the interval [–2, 2], where the slope of the tangents can be obtained by mean value theorem for the interval [–2, 2], are |
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Answer» y = x3 = f (x) f (2) = 8 and f (-2) = – 8 f’ (x) = 3x2 f’ (x) = [f (2) – f (-2)] / [2 – (-2)] = [8 – (-8)] / [4] = 3x2 x = ± 2 / √3 |
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