1.

The abscissae of two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinate are the roots fo the equations y^(2)+2py-q^(2)=0 then the radius of the circle with AB as diameter is

Answer»

`X^(2)+y^(2)+2ax+2py-b^(2)-Q^(2)=0`
`x^(2)+y^(2)+2ax+2py+b^(2)-q^(2)=0`
`x^(2)+y^(2)-2qx-2py+b^(2)+q^(2)=0`
`x^(2)+y^(2)+2ax-2py+b^(2)-q^(2)=0`

ANSWER :A


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