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The abscissae of two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinate are the roots fo the equations y^(2)+2py-q^(2)=0 then the radius of the circle with AB as diameter is |
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Answer» `X^(2)+y^(2)+2ax+2py-b^(2)-Q^(2)=0` |
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