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The absolute value of slope of common tangents to parabola `y^(2) = 8x` and hyperbola `3x^(2) -y^(2) =3` isA. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - B Tangent to `y^(2)=8x` is `y = mx + (2)/(m)` Tangent to `(x^(2))/(1) -(y^(2))/(3) =1` is `y = mx+-sqrt(m^(2)-3)` on comparing, we get `m = +-2` |
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