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The acceleration (a) of moving particle varies with displacement according to the following relation ` a = X^(2)+3X`, Then correct relation between velocity and displacement is :-A. `V=sqrt((X^(2))/(3)+(3X^(2))/(2)+C)`B. `V=sqrt((2)/(3)X^(3)+3X^(2)+C)`C. `V=((2)/(3)X^(3)+3X^(2)+C)`D. `V = 2x + 3` |
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Answer» Correct Answer - C `vec(a)=(dvec(v))/(dt)` is negative, but `vec(v)` = positive implies `vec(a)` and `vec(v)` are in opposite direction |
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