The acceleration - displacement graph of a particle moving in a straight line is given as in the figure . The initial velocity of the particle is zero. Find the velocity of the particle when displacement of the particle is s=12m.

The acceleration - displacement graph of a particle moving in a straig

1.	The acceleration - displacement graph of a particle moving in a straight line is given as in the figure . The initial velocity of the particle is zero. Find the velocity of the particle when displacement of the particle is s=12m.
Answer» Solution :From the equation `v^(2)-u^(2)=2as` as`=(v^(2)-u^(2))/2=`area under a-s graph INITIAL VELOCITY `u=0,` `:.`as `=v^(2)/2=` area under a-s graph. `:. V=sqrt(2("areaundera-s graph"))` `=sqrt[1/2(2)(2)+6xx2+1/2(2+4)2+1/2(2)4]2=sqrt(2xx24)=4sqrt3ms^(-1)`