The acceleration due to gravity on moon is 1/6th of that on the earth. If the length of the seconds pendulum is 96 m on the earth, what is its length on the moon ?

The acceleration due to gravity on moon is 1/6th of that on the earth.

1.	The acceleration due to gravity on moon is 1/6th of that on the earth. If the length of the seconds pendulum is 96 m on the earth, what is its length on the moon ?
Answer» <html><body><p></p>Solution :For <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a> pendulum , time period is <a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a> , `T= 2pi sqrt(l/g)` for <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> pendulum <br/>time remains <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> in both the planets , `l/g `= constant<br/> `therefore (l_m)/(g_m) = (l_e)/(g_e) ` (or) `(l_m)/((g_3)/(6)) = (96)/(g_e) = lm = 16 ` <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>.</body></html>