The acceleration due to gravity on moon is 1/6th of that on the earth. If the length of the seconds pendulum is 96 m on the earth, what is its length on the moon ?

The acceleration due to gravity on moon is 1/6th of that on the earth.

1.	The acceleration due to gravity on moon is 1/6th of that on the earth. If the length of the seconds pendulum is 96 m on the earth, what is its length on the moon ?
Answer» Solution :For SECONDS pendulum , time period is 2S , `T= 2pi sqrt(l/g)` for SIMPLE pendulum time remains CONSTANT in both the planets , `l/g `= constant `therefore (l_m)/(g_m) = (l_e)/(g_e) ` (or) `(l_m)/((g_3)/(6)) = (96)/(g_e) = lm = 16 ` CM.