The acceleration due to gravity on moon is 1//6th of that on the earth. If the length of the seconds pendulum is 96m on the earth, what is its length on the moon ?

The acceleration due to gravity on moon is 1//6th of that on the earth

1.	The acceleration due to gravity on moon is 1//6th of that on the earth. If the length of the seconds pendulum is 96m on the earth, what is its length on the moon ?
Answer» SOLUTION :For SECONDS pendulum time period is 2s `T= 2pisqrt((l)/(g))` for SIMPLE pendulum time remains constant in both the planets `(l)/(g)` = constant `:.(l_(m))/(g_(m))= (l_(E))/(g_(e))` or`(l_(m))/((g_(e))/(6))= (96)/(g_(e))` `l_(m)= 16 cm`