1.

The acceleration of a given particle in SHM is 0.4 ms^(-2) at a dispalcement of 0.1 m. What is the period of oscillation?

Answer»

Solution :A. Acceleration a = 0.4 m/s, Displacement y = 0.Im PERIOD of OSCILLATION
`T = 2pi SQRT(y/a) = 2pi sqrt((0.1)/(0.4)) =2pi 1/2 = PI ` , TIME period of oscillation T = `pi ` sec .


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