The acceleration of a particle is defined by the relation, a=−4x(−1+14x2) , where x is displacement along x− axis. All the quantities are in SI units. If velocity of the particle (v)=17 m/s when x=0, then the velocity of the particle when x=4 m is

The acceleration of a particle is defined by the relation, a=−4x(−

1.	The acceleration of a particle is defined by the relation, a=−4x(−1+14x2) , where x is displacement along x− axis. All the quantities are in SI units. If velocity of the particle (v)=17 m/s when x=0, then the velocity of the particle when x=4 m is
Answer» The acceleration of a particle is defined by the relation, $a = - 4 x (- 1 + \frac{1}{4} x^{2})$ , where $x$ is displacement along $x -$ axis. All the quantities are in $S I$ units. If velocity of the particle $(v) = 17 m/s$ when $x = 0$ , then the velocity of the particle when $x = 4 m$ is

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The acceleration of a particle is defined by the relation, a=−4x(−1+14x2) , where x is displacement along x− axis. All the quantities are in SI units. If velocity of the particle (v)=17 m/s when x=0, then the velocity of the particle when x=4 m is

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