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The acceleration of a particle is given by a (t)=(3.00m//s^(2))-(2.00 m//s^(3)) t. (a) Find the initial speed V_(0) such that the particle will have the same x-coordinate at t=5.00sas it had at t=0. (b) What will be the velocity at t=5.00s?

Answer»


ANSWER :(a)` 0.833 m//s` (B)`-9.17 m//s`


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