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The acceleration of paticle varies with time as : `a(t) = 3t^(2) +4` If the initial velocity of particle is `2 m//s`, find the velocity of particle at `t = 3sec`.A. `41 m//s`B. `4 m//s`C. `39 m//s`D. `27 m//s` |
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Answer» Correct Answer - A `a(t)=3t_(2)+4` `(dv)/(dt)=3t_(2)+4` `underset(2)overset(v)(int)dv =underset(0)overset(3)(int)(3t^(2)+4)dt` `v-t=t^(3)+4t|_(0)^(3)=27+12 rArr v=41//s`. |
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