1.

The acceleration of the particle at t = 3 s in the above figure is

Answer»

`(3PI)/(2) MS^(-2)`
`(3pi^(2))/(2) ms^(-2)`
`(pi^(2))/(2) ms^(-2)`
ZERO

Solution :`a = -OMEGA^(2) y =-((pi)/(2))^(2) xx (-2) = (pi^(2))/(2)`


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